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c^2+66c-67=0
a = 1; b = 66; c = -67;
Δ = b2-4ac
Δ = 662-4·1·(-67)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-68}{2*1}=\frac{-134}{2} =-67 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+68}{2*1}=\frac{2}{2} =1 $
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